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VOA 商务英语 lesson6

时间:2005-05-03 16:00:00

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(单词翻译)

Lesson 6
Dialog:
New word:memory(内存),storage(存储空间),application(应用程序)
M: In my research on the net, I learned One thing.
F:What’s that?
M: You can never have enough memory.(You =one 表泛指)
F:That works for(=goes for=适用) both people and computers.
M: design software takes a lot of computer memory.
F:Most computer applications take enormous amount.
M: But especially design software. Graphic1 files are huge.
F: So you need a lot of memory.
Q: Why do designers need a lot of memory?
A: design software takes a lot of memory.
Dialog 2:
Back up file(备用文件),crash(死机)
M: and storage, I need a lot of disk space to store those files
F:and to back them up(备份,动词).
M: Right, If the computer crashes , I don’t want to lose my work.
F: So you need a lot of storage on your computer,
M:And some back up storage device.
F: sure, you need to back up copies of your files
M: once my computer crashed , and I lost all my work. I had no back-up copies
F: no back up copies? Er, You only do that once.
Why are back up copied important?
In case you lose files.
Dialog 3: shareware link ( 共享软件连接) ,newsgroup(网络论坛)
M: Isn’t there shareware links available to help you back up files
F: sure!you can pull down(download) applications from a shareware site
M: I think my browser(浏览器) has a list of shareware links.
M: It must. point your browsers2 to one of these links.(表示轻而易举)
M: What about the newsgroups on shareware.
F: There must be newsgroups on shareware(表推断肯定)
M: There are newsgroups on everything.
F: cover all bases(留意一切,源于棒球运动) .looking every corner of the net.
Q:  What is Mr. Hyde looking for to help him back up files?
A: shareware
Small talk:(拒绝帮忙)
Q:Could you help me?
A: Sorry/unfortunately/I’d like to , but I can’t.

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Error Warning!

出错了

Error page: /mobile/?aid=1641&mid=3
Error infos: Got error 28 from storage engine
Error sql: select `l`.`tag`,`l`.`index`,`l`.`level_id`,`b`.`id`,`b`.`word`,`b`.`spell`,`b`.`explain`,`b`.`sentence`,`b`.`src` from `new_wordtaglist` `l` left join `new_word_base` `b` on `l`.`tag`=`b`.`word` where `l`.`arc_id`='1641' and `l`.`level_id`>='' group by `b`.`word` order by `l`.`index` asc

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